{"id":1596,"date":"2020-07-10T10:52:43","date_gmt":"2020-07-10T10:52:43","guid":{"rendered":"https:\/\/murreeroad.org\/physics10\/?p=1596"},"modified":"2020-10-26T00:08:17","modified_gmt":"2020-10-25T19:08:17","slug":"physics-10-chapter-18-examples","status":"publish","type":"post","link":"https:\/\/murreeroad.org\/physics10\/physics-10-chapter-18-examples\/","title":{"rendered":"Physics 10 Chapter 18 Examples"},"content":{"rendered":"<p style=\"text-align: center;\"><strong><span style=\"font-size: 18pt;\"><a id=\"top\"><\/a>Chapter 18 Numerical Problems Examples<\/span><\/strong><\/p>\n<p><strong><span style=\"color: #ff6600;\">Example 18.1:<\/span> Find the number of protons and neutrons in the nuclide defined by .\u00a0 <sup>13<\/sup>X<sub>6<\/sub>\u00a0<\/strong><br \/>\n<strong><span style=\"color: #3366ff;\">Solution:<\/span> <\/strong>From the symbol, we have Atomic number Z = number of protons =6<\/p>\n<p>Atomic mass A = number of protons + number of neutrons = 13<br \/>\nBut number of protons are 6, so number of neutrons will be 7.<br \/>\nSo the element is an isotope of carbon-6, and is written as<br \/>\n<sup>13<\/sup>X<sub>6<\/sub><\/p>\n<p><strong>NUCLEAR TRANSMUTATIONS<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-1597\" src=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/nuclear.jpg\" alt=\"\" width=\"402\" height=\"637\" srcset=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/nuclear.jpg 402w, https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/nuclear-189x300.jpg 189w\" sizes=\"(max-width: 402px) 100vw, 402px\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-1598\" src=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/ex18.2-3.jpg\" alt=\"\" width=\"400\" height=\"753\" srcset=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/ex18.2-3.jpg 400w, https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/ex18.2-3-159x300.jpg 159w\" sizes=\"(max-width: 400px) 100vw, 400px\" \/><\/p>\n<p><strong><span style=\"color: #ff6600;\">Example 18.4:<\/span> The C-14: C-12 ratio in a fossil bone is found to be <\/strong><strong>1\/4<sup>th<\/sup> that of the ratio in the bone of a living animal. The half- life of\u00a0<\/strong><br \/>\n<strong>C-14 is 5730 years what is the approximate age of the fossil?<\/strong><br \/>\n<strong><span style=\"color: #3366ff;\">Solution:<\/span> <\/strong>Since the ratio has been reduced by factor of 4 therefore, two half-lives have passed.<br \/>\nTherefore age of the fossil is given by: 2 x 5730 = 11460 years<\/p>\n<p>&nbsp;<\/p>\n<p><strong>Half Lives of Selected Isotopes<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-1599\" src=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/hf.jpg\" alt=\"\" width=\"385\" height=\"327\" srcset=\"https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/hf.jpg 385w, https:\/\/murreeroad.org\/physics10\/wp-content\/uploads\/2020\/07\/hf-300x255.jpg 300w\" sizes=\"(max-width: 385px) 100vw, 385px\" \/><\/p>\n<p style=\"text-align: center;\">&lt;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;&gt;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: right;\"><strong><a href=\"#top\">Goto Top<\/a><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Chapter 18 Numerical Problems Examples Example 18.1: Find the number of protons and neutrons in the nuclide defined by .\u00a0 13X6\u00a0 Solution: From the symbol, we have Atomic number Z = number of protons =6 Atomic mass A = number of protons + number of neutrons = 13 But number of protons are 6, so&hellip;&nbsp;<a href=\"https:\/\/murreeroad.org\/physics10\/physics-10-chapter-18-examples\/\" class=\"\" rel=\"bookmark\">Read More &raquo;<span class=\"screen-reader-text\">Physics 10 Chapter 18 Examples<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"neve_meta_sidebar":"","neve_meta_container":"","neve_meta_enable_content_width":"off","neve_meta_content_width":0,"neve_meta_title_alignment":"","neve_meta_author_avatar":"","neve_post_elements_order":"","neve_meta_disable_header":"","neve_meta_disable_footer":"","neve_meta_disable_title":""},"categories":[9],"tags":[],"_links":{"self":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1596"}],"collection":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/comments?post=1596"}],"version-history":[{"count":4,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1596\/revisions"}],"predecessor-version":[{"id":2101,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1596\/revisions\/2101"}],"wp:attachment":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/media?parent=1596"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/categories?post=1596"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/tags?post=1596"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}