{"id":1564,"date":"2020-07-10T08:59:29","date_gmt":"2020-07-10T08:59:29","guid":{"rendered":"https:\/\/murreeroad.org\/physics10\/?p=1564"},"modified":"2020-10-26T00:04:41","modified_gmt":"2020-10-25T19:04:41","slug":"physics-10-chapter-11-examples","status":"publish","type":"post","link":"https:\/\/murreeroad.org\/physics10\/physics-10-chapter-11-examples\/","title":{"rendered":"Physics 10 Chapter 11 Examples"},"content":{"rendered":"
<\/a>Chapter 11 Numerical Problems Examples<\/span><\/strong><\/p>\n <\/p>\n <\/p>\n Example 11.3:<\/span> Flash of lightning is seen 1.5 seconds earlier<\/span><\/strong> <—————————–><\/p>\n <\/p>\n <\/p>\n Goto Top<\/a><\/strong><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" Chapter 11 Numerical Problems Examples Example 11.3: Flash of lightning is seen 1.5 seconds earlier than the thunder. How far away is the cloud in which the flash \u00a0has occurred? (speed of sound = 332 m s-1 ). Solution:\u00a0 Given that, time t = 1.5 s, speed of sound v = 332 m s-1 .… Read More »Physics 10 Chapter 11 Examples<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"neve_meta_sidebar":"","neve_meta_container":"","neve_meta_enable_content_width":"off","neve_meta_content_width":0,"neve_meta_title_alignment":"","neve_meta_author_avatar":"","neve_post_elements_order":"","neve_meta_disable_header":"","neve_meta_disable_footer":"","neve_meta_disable_title":""},"categories":[9],"tags":[],"_links":{"self":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1564"}],"collection":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/comments?post=1564"}],"version-history":[{"count":3,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1564\/revisions"}],"predecessor-version":[{"id":2096,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1564\/revisions\/2096"}],"wp:attachment":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/media?parent=1564"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/categories?post=1564"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/tags?post=1564"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nthan the thunder. How far away is the cloud in which the flash<\/strong><\/span>
\n\u00a0has occurred? (speed of sound = 332 m s-1<\/sup> ).<\/strong><\/span>
\nSolution:\u00a0 <\/strong>Given that, time t = 1.5 s, speed of sound v = 332 m s-1<\/sup> .<\/span>
\n\u00a0Therefore, distance of the cloud S = vt = 1.5 s \u00d7 332 m s-1<\/sup> = 498 m.<\/span><\/p>\n