{"id":1472,"date":"2020-07-03T17:29:26","date_gmt":"2020-07-03T17:29:26","guid":{"rendered":"https:\/\/murreeroad.org\/physics10\/?p=1472"},"modified":"2020-07-03T18:53:24","modified_gmt":"2020-07-03T18:53:24","slug":"physics-10th-chapter-10-numerical-problems","status":"publish","type":"post","link":"https:\/\/murreeroad.org\/physics10\/physics-10th-chapter-10-numerical-problems\/","title":{"rendered":"Physics 10th chapter 10 Numerical Problems"},"content":{"rendered":"\n\n\n
Numerical Problems\u00a0<\/a><\/strong><\/span><\/td>\n<\/tr>\n<\/thead>\n<\/table>\n

Q.10.1 The time period of a simple pendulum is 2 s. What will be its length on the Earth? What will be its length on the Moon if gm<\/sub> =ge<\/sub> \/6? where ge<\/sub> = 10 m s-2<\/sup><\/a><\/p>\n

Q.10.2 A pendulum of length 0.99 m is taken to the Moon by an astronaut. The period of the pendulum is 4.9 s. What is the value of g on the surface of the Moon?<\/a><\/p>\n

Q.10.3 Find the time periods of a simple pendulum of 1 metre length, placed on Earth and\u00a0on Moon. The value of g on the surface of Moon is 1\/6 of its value on Earth,<\/a>
\n
where g is 10 m s-2<\/sup> .<\/a><\/p>\n

Q.10.4 A simple pendulum completes one vibration in two seconds. Calculate its length, when g = 10.0 m s-2<\/sup> .<\/a><\/p>\n

Q.10.5 If 100 waves pass through a point of a medium in 20 seconds, what is the frequency and the time period of the wave? If its wavelength is 6 cm, calculate the wave speed.<\/a><\/p>\n

Q. 10.6 A wooden bar vibrating into the water surface in a ripple tank has a frequency of 12 Hz. The resulting wave has a wavelength of 3 cm. What is the speed of the wave?<\/a><\/p>\n

Q. 10.7 A transverse wave produced on a spring has a frequency of 190 Hz and travels along the length of the spring of 90 m, in 0.5 s.<\/a>
\n(a) What is the period of the wave?
\n(b) What is the speed of the wave?
\n(c) What is the wavelength of the wave?<\/p>\n

Q.10.8 Water waves in a shallow dish are 6.0 cm long. At one point, the water moves up and down at a rate of 4.8 oscillations per second.<\/a>
\n(a) What is the speed of the water waves?
\n(b) What is the period of the water waves?<\/p>\n

Q.10.9 At one end of a ripple tank 80 cm across, a 5 Hz vibrator produces waves whose wavelength is 40 mm. Find the time the waves need to cross the tank.<\/a><\/p>\n

Q.10.10 What is the wavelength of the radio waves transmitted by an FM station at 90 MHz? \u00a0where 1M = 106<\/sup> , and speed of radio wave is 3 x 108<\/sup> m s-1<\/sup><\/a> .\u00a0 <\/a><\/p>\n

Q.10.1 The time period of a simple pendulum is 2 s. What will be its length on the Earth? What will be its length on the Moon if gm<\/sub> = ge<\/sub> \/6? where ge<\/sub> = 10 m s-2<\/sup><\/strong><\/p>\n

\u00a0\"\"<\/a><\/strong><\/p>\n

Q.10.2 A pendulum of length 0.99 m is taken to the Moon by an astronaut. The period of the pendulum is 4.9 s. What is the value of g on the surface of the Moon?\u00a0<\/strong><\/p>\n

\u00a0\"\"<\/a><\/strong><\/p>\n

Q.10.3 Find the time periods of a simple pendulum of 1 metre length, placed on Earth and on Moon. The value of g on the surface of Moon is 1\/6 of its value on Earth, <\/strong>where g is 10 m s-2<\/sup> .\u00a0<\/strong><\/p>\n

\"\"<\/a><\/strong><\/p>\n

Tm<\/sub> = 2 x ( 3.14 ) x ( 0.774 )<\/strong><\/p>\n

Tm<\/sub> = 4.9 sec. Time period on Moon.<\/strong><\/p>\n

Q.10.4 A simple pendulum completes one vibration in two seconds. Calculate its length, when g = 10.0 m s-2<\/sup> .\u00a0<\/strong><\/p>\n

Solution: Given Data:<\/strong><\/p>\n

\"\"<\/a><\/strong><\/p>\n

\u00a0<\/strong><\/p>\n

Q.10.5 If 100 waves pass through a point of a medium in 20 seconds, what is the frequency and the time period of the wave? If its wavelength is 6 cm, calculate the wave speed.\u00a0<\/strong><\/p>\n

\u00a0\"\"<\/a><\/strong><\/p>\n

Q. 10.6 A wooden bar vibrating into the water surface in a ripple tank has a frequency of 12 Hz. The resulting wave has a wavelength of 3 cm. What is the speed of the wave?\u00a0<\/strong><\/p>\n

Solution: Given Data:<\/strong><\/p>\n

Frequency f = 12 Hz<\/strong><\/p>\n

Wavelength \u03bb = 3cm = 0.03m\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 we know 1 m = 100 cm<\/strong><\/p>\n

Speed v = ?<\/strong><\/p>\n

Formula:\u00a0 v = f \u03bb<\/strong><\/p>\n

v = (12) x (0.03)<\/strong><\/p>\n

v = 0.36 ms-1\u00a0 \u00a0 <\/a><\/sup><\/strong><\/p>\n

Q. 10.7 A transverse wave produced on a spring has a frequency of 190 Hz and travels along the length of the spring of 90 m, in 0.5 s.<\/strong>
\n(a) What is the period of the wave?<\/strong>
\n(b) What is the speed of the wave?<\/strong>
\n(c) What is the wavelength of the wave?<\/strong><\/p>\n

Solution: Given Data:<\/strong><\/p>\n

Frequency f = 190 Hz<\/strong><\/p>\n

Wavelength \u03bb = 3cm = 0.03m\u00a0 \u00a0 \u00a0 we know 1m = 100 cm<\/strong><\/p>\n

Length of the spring d = 90m\u00a0<\/strong><\/p>\n

(a) T = ?\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(b) Speed v = ?\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(c)\u00a0 \u00a0 \u00a0 Wavelength\u00a0 \u03bb = ?<\/strong><\/p>\n

(a) <\/strong><\/p>\n

Formula:\u00a0 \u00a0f = 1\/T<\/strong><\/p>\n

T = 1\/f\u00a0 \u00a0=\u00a0 1\/190\u00a0<\/strong><\/p>\n

T = 0.01 second<\/strong><\/p>\n

(b)<\/strong><\/p>\n

Formula: d = vt\u00a0<\/strong><\/p>\n

v = d\/t<\/strong><\/p>\n

v = 90\/0.5<\/strong><\/p>\n

v = 180 ms-1<\/sup><\/strong><\/p>\n

(c)<\/strong><\/p>\n

Formula: v = f \u03bb<\/strong><\/p>\n

\u03bb = v\/f<\/strong><\/p>\n

\u03bb = 180\/190<\/strong><\/p>\n

\u03bb = 0.95m\u00a0 \u00a0 <\/a><\/strong><\/p>\n

Q.10.8 Water waves in a shallow dish are 6.0 cm long. At one point, the water moves up and down at a rate of 4.8 oscillations per second.<\/strong>
\n(a) What is the speed of the water waves?<\/strong>
\n(b) What is the period of the water waves?<\/strong><\/p>\n

Solution: Given Data:<\/strong><\/p>\n

Length of waves (wavelength) \u03bb = 6.0cm = 0.06m\u00a0 \u00a0 \u00a0 \u00a0 we know that 1m = 100cm<\/strong><\/p>\n

No. of oscillation frequency f = 4.8Hz<\/strong><\/p>\n

(a) Speed v = ?\u00a0 \u00a0(b) Period T = ?<\/strong><\/p>\n

(a)<\/strong><\/p>\n

Formula: f = 1\/T<\/strong><\/p>\n

T = 1\/f<\/strong><\/p>\n

T = 1\/4.8 = 0.21 second<\/strong><\/p>\n

(b)<\/strong><\/p>\n

Formula: v = f \u03bb<\/strong><\/p>\n

v = (4.8) x (0.06)<\/strong><\/p>\n

v = 0.29 ms-1\u00a0 \u00a0 <\/a><\/sup><\/strong><\/p>\n

Q.10.9 At one end of a ripple tank 80 cm across, a 5 Hz vibrator produces waves whose wavelength is 40 mm. Find the time the waves need to cross the tank.\u00a0<\/strong><\/p>\n

Solution: given Data:<\/strong><\/p>\n

Length of ripple tank d = 80cm = 0.8 m\u00a0 \u00a0 \u00a0we know that\u00a0 1m = 100cm<\/strong><\/p>\n

Frequency f = 5 Hz<\/strong><\/p>\n

Wavelength \u03bb = 40mm = 0.04m\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 we know that\u00a0 1m = 1000mm<\/strong><\/p>\n

Time to cross the wave t = ?<\/strong><\/p>\n

First we find the speed of wave v = ?<\/strong><\/p>\n

Formula v = f \u03bb<\/strong><\/p>\n

Putting the values we get v = (5) x (0.04)<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 v = 0.2 ms-1<\/sup><\/strong><\/p>\n

Formula\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0d = vt<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 t = d\/v<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 t = 0.8\/0.2<\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 t = 4 second\u00a0 <\/a><\/strong><\/p>\n

Q.10.10 What is the wavelength of the radio waves transmitted by an FM station at 90 MHz? \u00a0where 1M = 106<\/sup> , and speed of radio wave is 3 x 108<\/sup> m s-1<\/sup> .\u00a0<\/strong><\/p>\n

Solution: Given data:<\/strong><\/p>\n

Frequency f = 90MHz\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (Given 1M = 106<\/sup> )<\/strong><\/p>\n

Speed of radio waves is v= c = 3 x 108<\/sup> ms-1<\/strong><\/p>\n

Formula\u00a0 \u00a0v = c = f \u03bb<\/strong><\/p>\n

\u03bb\u00a0 = c\/f<\/strong><\/p>\n

\u03bb\u00a0 = 3 x 108<\/sup>\/90 x 106<\/sup><\/strong><\/p>\n

\u03bb = 3 x 108<\/sup> \/ 90 x 106<\/sup><\/strong><\/p>\n

\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u03bb\u00a0 \u00a0= 3.33m<\/strong><\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

Numerical Problems\u00a0 Q.10.1 The time period of a simple pendulum is 2 s. What will be its length on the Earth? What will be its length on the Moon if gm =ge \/6? where ge = 10 m s-2 Q.10.2 A pendulum of length 0.99 m is taken to the Moon by an astronaut. The… Read More »Physics 10th chapter 10 Numerical Problems<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"neve_meta_sidebar":"","neve_meta_container":"","neve_meta_enable_content_width":"off","neve_meta_content_width":0,"neve_meta_title_alignment":"","neve_meta_author_avatar":"","neve_post_elements_order":"","neve_meta_disable_header":"","neve_meta_disable_footer":"","neve_meta_disable_title":""},"categories":[9],"tags":[],"_links":{"self":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1472"}],"collection":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/comments?post=1472"}],"version-history":[{"count":9,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1472\/revisions"}],"predecessor-version":[{"id":1489,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/posts\/1472\/revisions\/1489"}],"wp:attachment":[{"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/media?parent=1472"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/categories?post=1472"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/murreeroad.org\/physics10\/wp-json\/wp\/v2\/tags?post=1472"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}